L'exercice suivant est automatiquement et aléatoirement généré par ataraXy.
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Exercice
Calculer \[\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{\left(-\dfrac{42}{11}-5\right)+2-\left(-7\right)\times\left(-\dfrac{78}{11}\right)\times1}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{105}{2}\times\left(-\dfrac{41}{11}\right)\times\left(-\dfrac{41}{11}\right)\times\left(-2-\dfrac{19}{2}-\dfrac{41}{11}-\dfrac{35}{3}\right)}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5-\left(-\dfrac{42}{11}\right)\times12\times\dfrac{108}{5}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\]
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Exercice
On a \( X=\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{\left(-\dfrac{42}{11}-5\right)+2-\left(-7\right)\times\left(-\dfrac{78}{11}\right)\times1}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{105}{2}\times\left(-\dfrac{41}{11}\right)\times\left(-\dfrac{41}{11}\right)\times\left(-2-\dfrac{19}{2}-\dfrac{41}{11}-\dfrac{35}{3}\right)}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5-\left(-\dfrac{42}{11}\right)\times12\times\dfrac{108}{5}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}=\dfrac{3.658696811302E+20}{87768491298468750}\) . Voici le détail :
\begin{eqnarray*}
X &=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{97}{11}+2-\left(-7\right)\times\left(-\dfrac{78}{11}\right)\times1}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{105}{2}\times\left(-\dfrac{41}{11}\right)\times\left(-\dfrac{41}{11}\right)\times\left(-2-\dfrac{19}{2}-\dfrac{41}{11}-\dfrac{35}{3}\right)}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5-\left(-\dfrac{42}{11}\right)\times12\times\dfrac{108}{5}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{97}{11}+2-\dfrac{546}{11}\times1}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{105}{2}\times\left(-\dfrac{41}{11}\right)\times\left(-\dfrac{41}{11}\right)\times\left(-2-\dfrac{19}{2}-\dfrac{41}{11}-\dfrac{35}{3}\right)}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5-\left(-\dfrac{42}{11}\right)\times12\times\dfrac{108}{5}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{97}{11}+2-\dfrac{546}{11}}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{105}{2}\times\left(-\dfrac{41}{11}\right)\times\left(-\dfrac{41}{11}\right)\times\left(-2-\dfrac{19}{2}-\dfrac{41}{11}-\dfrac{35}{3}\right)}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5-\left(-\dfrac{42}{11}\right)\times12\times\dfrac{108}{5}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{97}{11}+2-\dfrac{546}{11}}{\left(-\dfrac{35}{3}\right)\times12\times\left(-\dfrac{4305}{22}\right)\times\left(-\dfrac{41}{11}\right)\times\left(-2-\dfrac{19}{2}-\dfrac{41}{11}-\dfrac{35}{3}\right)}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5-\left(-\dfrac{42}{11}\right)\times12\times\dfrac{108}{5}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{97}{11}+2-\dfrac{546}{11}}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{176505}{242}\times\left(-2-\dfrac{19}{2}-\dfrac{41}{11}-\dfrac{35}{3}\right)}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5-\left(-\dfrac{42}{11}\right)\times12\times\dfrac{108}{5}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{97}{11}+2-\dfrac{546}{11}}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{176505}{242}\times\left(-\dfrac{23}{2}-\dfrac{41}{11}-\dfrac{35}{3}\right)}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5-\left(-\dfrac{42}{11}\right)\times12\times\dfrac{108}{5}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{97}{11}+2-\dfrac{546}{11}}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{176505}{242}\times\left(-\dfrac{335}{22}-\dfrac{35}{3}\right)}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5-\left(-\dfrac{42}{11}\right)\times12\times\dfrac{108}{5}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{97}{11}+2-\dfrac{546}{11}}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{176505}{242}\times-\dfrac{1775}{66}}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5-\left(-\dfrac{42}{11}\right)\times12\times\dfrac{108}{5}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{97}{11}+2-\dfrac{546}{11}}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{176505}{242}\times-\dfrac{1775}{66}}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5-\left(-\dfrac{504}{11}\right)\times\dfrac{108}{5}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{97}{11}+2-\dfrac{546}{11}}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{176505}{242}\times-\dfrac{1775}{66}}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5+\dfrac{54432}{55}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{75}{11}-\dfrac{546}{11}}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{176505}{242}\times-\dfrac{1775}{66}}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5+\dfrac{54432}{55}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{621}{11}}{\left(-\dfrac{35}{3}\right)\times12\times\dfrac{176505}{242}\times-\dfrac{1775}{66}}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5+\dfrac{54432}{55}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{621}{11}}{\left(-140\right)\times\dfrac{176505}{242}\times-\dfrac{1775}{66}}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5+\dfrac{54432}{55}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{621}{11}}{\left(-\dfrac{12355350}{121}\right)\times-\dfrac{1775}{66}}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5+\dfrac{54432}{55}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{621}{11}}{\dfrac{21930746250}{7986}}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\left(5+\dfrac{54432}{55}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{\dfrac{-\dfrac{621}{11}}{\dfrac{21930746250}{7986}}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\dfrac{54707}{55}\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}+\dfrac{-\dfrac{4959306}{241238208750}}{\dfrac{105}{2}}\right)-\dfrac{\left(-4\right)\times\dfrac{54707}{55}\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}-\dfrac{9918612}{25330011918750}\right)-\dfrac{\left(-4\right)\times\dfrac{54707}{55}\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}-\dfrac{9918612}{25330011918750}\right)-\dfrac{\left(-\dfrac{218828}{55}\right)\times1\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}-\dfrac{9918612}{25330011918750}\right)-\dfrac{\left(-\dfrac{218828}{55}\right)\times\left(-4\right)}{-\dfrac{42}{11}}\\&=&\left(-\dfrac{35}{3}+5\right)-\left(-\dfrac{78}{11}-\dfrac{9918612}{25330011918750}\right)-\dfrac{\dfrac{875312}{55}}{-\dfrac{42}{11}}\\&=&-\dfrac{20}{3}-\left(-\dfrac{78}{11}-\dfrac{9918612}{25330011918750}\right)-\dfrac{\dfrac{875312}{55}}{-\dfrac{42}{11}}\\&=&-\dfrac{20}{3}+\dfrac{1975741038767232}{278630131106250}-\dfrac{\dfrac{875312}{55}}{-\dfrac{42}{11}}\\&=&-\dfrac{20}{3}+\dfrac{1975741038767232}{278630131106250}+\dfrac{437656}{105}\\&=&\dfrac{354620494176696}{835890393318750}+\dfrac{437656}{105}\\&=&\dfrac{3.658696811302E+20}{87768491298468750}\\
\end{eqnarray*}